10x^2+11x+4=10

Solution for 10x^2+11x+4=10 equation:

10x^2+11x+4=10

We move all terms to the left:

10x^2+11x+4-(10)=0

We add all the numbers together, and all the variables

10x^2+11x-6=0

a = 10; b = 11; c = -6;
Δ = b2-4ac
Δ = 112-4·10·(-6)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-19}{2*10}=\frac{-30}{20}
=-1+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+19}{2*10}=\frac{8}{20}
=2/5
$